过点P(-根号3,0)作直线l交椭圆11X^2+Y^2=9于M、N,问L的斜率为多大时,以M,N为直径的圆过原点
2个回答

设M(x1,y1),N(x2,y2)

OM⊥ON

∴x1x2+y1y2=0

联立y=k(x+√3),11x²+y²=9

11x²+k²(x+√3)²=9

(11+k²)x²+2√3k²x+3k²-9=0

△=(2√3k²)²-4(11+k²)(3k²-9)>0

根据韦达定理有

x1x2=(3k²-9)/(11+k²)

y1y2=k(x1+√3)*k(x2+√3)=k²[x1x2+√3(x1+x2)+3]

=k²[(3k²-9)/(11+k²)-√3*2√3k²/(11+k²)+3]

=-x1x2=(9-3k²)/(11+k²)

k²=1/3满足△>0

k=±√3/3