4xdx-3ydy=3x^2ydy-2xy^2dx的通解
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∵4xdx-3ydy=3x^2ydy-2xy^2dx

==>2d(x^2)-(3/2)d(y^2)=(3/2)x^2d(y^2)-y^2d(x^2)

==>y^2d(x^2)+2d(x^2)=(3/2)x^2d(y^2)+(3/2)d(y^2)

==>(y^2+2)d(x^2)=(3/2)(x^2+1)d(y^2)

==>d(x^2)/(x^2+1)=(3/2)d(y^2)/(y^2+2)

==>d(x^2+1)/(x^2+1)=(3/2)d(y^2+2)/(y^2+2)

==>ln(x^2+1)=(3/2)ln(y^2+2)+ln│C│ (C是常数)

==>x^2+1=C(y^2+2)^(3/2)

==>(x^2+1)/(y^2+2)^(3/2)=C

∴原方程的通解是(x^2+1)/(y^2+2)^(3/2)=C.

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