f(x)=2*sin^2(π/4+x)-√3*cos2x
1个回答

1,前面减去1 后面添上一个1

2,cos2α=1-2sin^2α 2*sin^2(π/4+x)-1= - cos(π/2+2x)

3, cos(π/2+α)=-sinα - cos(π/2+2x)=sin2x

4,sin2x-√3*cos2x=2(1/2sin2x-√3/2*cos2x) -----提取一个2

=2(sin30°sin2x-cos30°cos2x) -----cosα*cosβ-sinα*sinβ=cos(α+β)

= -2cos(2x+π/6) ------答案不太对啊

即使看成=2(cos60°sin2x-sin60°cos2x) -----sinα*cosβ-cosα*sinβ=sin(α-β)

=2sin(2x-π/3)