1)2x^2-mx-m^2=0 (2)2x^2-(3m-n)x-2m^2+3mn-n^2=0 公式法做
1个回答

1)2x^2-mx-m^2=0

a=2,b=-m,c=-m²

b²-4ac=m²+8m²=9m²

∴x12=[-b±√(b²-4ac)]/2a

=[m±√9m²)/4

=(m±3m)/4

∴x1=m x2=-m/2

(2)2x^2-(3m-n)x-2m^2+3mn-n^2=0

a=2 ,b=-(3m-n) ,c=-2m²+3mn-n²

b²-4ac=(3m-n)²-8(-2m²+3mn-n²)

=25m²-30mn+9n²

=(5m-3n)²

∴x12=[-b±√(b²-4ac)]/2a

=[(3m-n)±√(5m-3n)²]/4

=[3m-n±(5m-3n)]/4

∴x1=2m-n x2=-m/2+n/2