1)2x^2-mx-m^2=0
a=2,b=-m,c=-m²
b²-4ac=m²+8m²=9m²
∴x12=[-b±√(b²-4ac)]/2a
=[m±√9m²)/4
=(m±3m)/4
∴x1=m x2=-m/2
(2)2x^2-(3m-n)x-2m^2+3mn-n^2=0
a=2 ,b=-(3m-n) ,c=-2m²+3mn-n²
b²-4ac=(3m-n)²-8(-2m²+3mn-n²)
=25m²-30mn+9n²
=(5m-3n)²
∴x12=[-b±√(b²-4ac)]/2a
=[(3m-n)±√(5m-3n)²]/4
=[3m-n±(5m-3n)]/4
∴x1=2m-n x2=-m/2+n/2