1 、x+y=8 xy=6 求x²+3xy+2y²/x²y+2xy²
1个回答

1 、x+y=8 xy=6 求x²+3xy+2y²/x²y+2xy²的值.

x²+3xy+2y²/x²y+2xy²

=(x+2y)(x+y)/xy(x+2y)

=(x+y)/xy x+y=8 xy=6

=8/6

=4/3

2、3/a=4/b=5/c,求分式 ab-bc+ac/a²+b²+c²的值

∵3/a=4/b=5/c,

∴b=4a/3

c=5a/3

∴ab-bc+ac/a²+b²+c²

=(a*4a/3-4a/3*5a/3+a*5a/3)/(a²+16a²/9+25a²/9)

=(4a²/3-20a²/9+5a²/3)/(50a²/9)

=(27a²/9-20a²/9)/(50a²/9)

=(7a²/9)/(50a²/9)

=7/50