B.99*100*101
n(n+1)=n^2+n
1^2+2^2+...+n^2
=n(n+1)(2n+1)/6
3*(1*2+2*3+3*4+4*5+5*6+...+99*100)
=3*(1^2+1+2^2+2+3^2+3+4^2+4+5^2+5+...+99^2+99)
=3*(1^2+2^2+3^2+4^2+5^2+...+99^2+1+2+3+4+5+.+99)
=3*[99*(99+1)*(2*99+1)/6+(1+99)*99/2]
=3*[99*100*199/6+100*99/2]
=99*50*199+50*99*3
=99*50*(199+3)
=99*50*202
=99*100*101