与y轴交点:x = 0
(0-2sqrt(3))^2 + (y -2)^2 = 16
(y -2)^2 = 4
y = 0 或 y = 4
A,B两点:(0,0),(0,4).AB = 4
与x轴的交点:y = 0
(x - 2sqrt(3))^2 + (0-2)^2 = 16
(x - 2sqrt(3))^2 = 12
x = 0 或 x = 4sqrt(3)
P点:(4sqrt(3),0)
AP= 4sqrt(3)
APB为直角三角型 (角PAB为直角),tg(APB) = AB/AP = 4/(4sqrt(3))
= 1/sqrt(3)
角APB=30度