已知点A是圆F1：（x十3^1/2）^2十y^2=16上任意一点,F1为圆心,点F2与F1关于原点对称.线段AF2的中垂
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F1(-√3,0),F2(√3,0)

xN=0.5xA+0.5√3,yN=0.5yA

(xA+√3)^2+(yA)^2=16

M(x,y)

[(yM-yN)/(xM-xN)]*[yA/(xA-√3)=-1

[(y-0.5yA)/(x-0.5xA-0.5√3)]*[yA/(xA-√3)]=-1

y*yA+x*xA-0.5(xA)^2-0.5(yA)^2-√3*(x-0.5√3)=0

y*yA+x*xA-0.5[(xA+√3)^2+(yA)^2]+√3xA+1.5-√3*(x-0.5√3)=0

y*yA+x*xA-0.5*16+√3xA+1.5-√3*(x-0.5√3)=0

y*yA+(x+√3)xA-4-√3*x=0.(1)

k(AM)=yA/(xA+√3)=y/(x+√3).(2)

xA=,yA=

(xA+√3)^2+(yA)^2=16

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