怎么在matlab中画出方程11.29x=0.45[11.29(x+y)]^0.78的曲线,其中0
2个回答
clear,clc;
x=0:0.02:0.7;
y=(11.29*x/0.45).^(-0.78)/11.29-x
plot(x,y)
（
y =
Columns 1 through 14
Inf 0.1317 0.0483 0.0044 -0.0286 -0.0568 -0.0825 -0.1068 -0.1300 -0.1527 -0.1748 -0.1966 -0.2182 -0.2395
Columns 15 through 28
-0.2606 -0.2817 -0.3026 -0.3234 -0.3441 -0.3647 -0.3853 -0.4059 -0.4264 -0.4469 -0.4673 -0.4877 -0.5081 -0.5284
Columns 29 through 36
-0.5487 -0.5690 -0.5893 -0.6096 -0.6298 -0.6501 -0.6703 -0.6905
）
注：你给的范围0
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