2道数学题(因式分解)1.已知:x、y为实数,求5x²-3xy+4y²+12x+25最小值2.整数a、b满足6ab=9a
1个回答

1.5x²-3xy+4y²+12x+25

=9/16x²-3xy+4y²+71/16x²+12x+25

=(3/4x-2y)²+71/16x²+12x+576/71+1199/71

=(3/4x-2y)²+71/16(x+96/71)²+1199/71

>=1199/71,

所以5x²-3xy+4y²+12x+25最小值为1199/71.

2.因为整数a、b满足6ab=9a-10b+303,所以可解得

b=(9a+303)/(6a+10) = 3/2 + 288/(6a+10) = 3/2 + 144/(3a+5)

显然为了保证b为整数,必须

144/(3a+5) = k/2,也即

(3a+5)*k=288.

288的质因数分解为288=2^5*3^2,因为3a+5是288的因子,

所以3a+5一定是2^p * 3^q的形式(p