sin40(tan10-√3)的值
1个回答
原式=sin40*(tan10-tan60)
=sin40(sin10/cos10-sin60/cos60)
=sin40(sin10cos60-cos10sin60)/(cos10cos60)
=sin40*(-sin50/(sin80sin30))
=-sin40cos40/(2sis40cos40*1/2)
=-1
sin40°(tan10°-根号3)
=sin40*sin10/cos10-根号3*sin40
=sin40*cos80/cos10-根号3*sin40
=sin40*cos80/2sin40*cos40-根号3*sin40
=(1/2)*cos80/cos40-根号3*sin40
=[(1/2)*cos80-根号3sin40*sin40]/cos40
=[(1/2)cos80-根号3/2*sin80]/cos40
=(sin30*cos80-cos30*sin80)/cos40
=sin(30-80)/cos40
=-sin50/cos40
=-1
