sin40(tan10-根号3)
1个回答

1、原式=sin40°(sin10°/cos10°-√3)

=2sin40°/cos10 °(sin10°sin30°-cos 10°cos30°)

=-2sin40°/cos10 °]cos(30°+10°)

=-2sin40°cos40°/cos10 °

=-sin80°/cos10°

=-cos10°/cos10°

=-1.

2、原式=2sin70°cos10°(sin60°*sin20°/cos20°-cos60 °)/cos70°

=2cos20°cos10°/cos20 °(sin60°*sin20°-cos60 °cos20°)/cos70°

=[-2cos10°]cos(60°+20°)/cos70°

=[-2cos10°*cos80°/sin20°

=[-2cos10°*sin10 °/sin20°

=-sin20°/sin20°

=-1.