1)第二次取出的球都是新球的概率
(C(3,3)*C(9,3)+C(3,2)*C(9,1)*C(8,3)+C(3,1)*C(9,2)*C(7,3)+C(9,3)*C(6,3))/(C(12,3)*C(12,3))
=(84+3*9*56+3*36*35+84*20)/(220*220)
=(84+1512+3780+1680)/48400
=7056/48400
≈0.145785124
2)已知第二次取出的球都是新球,第一次取到都是新球的概率
C(9,3)*C(6,3)/(C(3,3)*C(9,3)+C(3,2)*C(9,1)*C(8,3)+C(3,1)*C(9,2)*C(7,3)+C(9,3)*C(6,3))
=84*20/(84+3*9*56+3*36*35+84*20)
=1680/7056
=5/21