∫(x²e^x)/(x+2)²dx
1个回答

∫(x²e^x)/(x+2)²dx

=∫(x²+4x+4-4x-8+4)e^x/(x+2)²dx

=∫((x+2)²-4x-8+4)e^x/(x+2)²dx

=∫(x+2)²e^x/(x+2)²dx - 4∫(x+2)e^x/(x+2)²dx + 4∫e^x/(x+2)²dx

=∫e^xdx - 4∫e^x/(x+2)dx + 4∫e^x/(x+2)²dx

=e^x - 4∫1/(x+2)d(e^x) + 4∫e^x/(x+2)²dx

=e^x - 4e^x/(x+2) - 4∫(e^x)/(x+2)² + 4∫e^x/(x+2)²dx

=e^x - 4e^x/(x+2) + C

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