sin15度cos15度tan15度和sin75度cos75度tan75度怎样求 不光要结果
1个回答

sin15°=sin(45°-30°)

=sin45°cos30°-sin30°cos45°

=√2/2×√3/2-1/2×√2/2

=√6/4-√2/4

=(√6-√2)/4

cos75°=sin15°=(√6-√2)/4

Cos15°=cos(45°-30°)

=cos45°cos30°+sin30°sin45°

=√2/2×√3/2+1/2×√2/2

=√6/4+√2/4

=(√6+√2)/4

sin75°=cos15°=(√6+√2)/4

tan15°=sin15°/cos15°

=(√6-√2)/4÷(√6+√2)/4

=2-√3

tan75°=sin75°/cos75°

=(√6+√2)/4÷(√6-√2)/4

=2+√3