下面各题怎样简便就怎样算.[9/11]-([9/2]+[3/1])[6/5]+[8/5]+[6/1]+[8/3]8-[1
1个回答

解题思路:(1)先算括号里的加法,再算外边的减法;

(2)按从左到右的运算顺序计算;

(3)根据减法的性质计算;

(4)根据减法的性质计算.

(1)[9/11]-([9/2]+[3/1])

=[9/11]-[15/2]

=-[147/22]

(2)[6/5]+[8/5]+[6/1]+[8/3]

=[6/5]+[8/5]+[6/1]+[8/3]

=[14/5]+6+2[2/3]

=8[4/5]+2[2/3]

=11[7/15]

(3)8-[16/5]-[16/11]

=8-([16/5]+[16/11])

=8-4[36/55]

=3[19/55]

(4)[10/9]-([6/5]-[5/3])

=[10/9]+[5/3]-[6/5]

=[25/9]-[6/5]

=[71/45]

点评:

本题考点: 分数的加法和减法;运算定律与简便运算.

考点点评: 计算四则混合运算时,要按照运算顺序,先算乘除,后算加减,有括号的先算括号里面的,再算括号外面的.能简算的要简算.