已知函数f(x)=cosx/2(sinx/2+cosx/2)-1/2
1个回答

(1)

f(x)=cosx/2(sinx/2+cosx/2)-1/2

=sinx/2cosx/2+cos²x/2-1/2

=1/2sinx+1/2(1+cosx)-1/2

=1/2(sinx+cosx)

=√2/2(√2/2sinx+√2/2cosx)

=√2/2sin(x+π/4)

由x+π/4=kπ,k∈Z

得x=kπ-π/4,k∈Z

∴f(x)图像对称中心为(kπ-π/4,0)k∈Z

(2)

x∈[π,9π/4]时,x+π/4∈[5π/4,5π/2]

当x+π/4∈[5π/4,3π/2],即x∈[π,5π/4],f(x)递增

当x+π/4∈[3π/2,2π],即x∈[5π/4,7π/4],f(x)递减

当x+π/4∈[2π,5π/2],即x∈[7π/4,9π/4],f(x)递增

f(x)递增区间为[π,5π/4],[7π/4,9π/4]

递减区间为[5π/4,7π/4]