如图,在平面直角坐标系中,点A,B的坐标分别为(-5,0)和(5,0),
1个回答

(1)题不全

(2)

从C向x轴做垂线,垂足C'

AE = 6, BE = AB - AE = 10 - 6 = 4

CC'平分BD和BE,BC' = BE/2 = 2, C'(3, 0)

圆x² + y² = 25

代入x = 3, y = 4 (y >0, C与C'横坐标相同)

C(3, 4)

BC= √[(3 - 5)² + (4 - 0)²] = 2√5

(3)

C(p, q), p² + q² = 25, 0 < p < 5, 0 < q < 5

C'(p, 0), C'B = 5 - p, EB = 2C'B = 10 - 2p

E(2p - 5, 0)

D(2p - 5, 2q)

AC: (y - 0)/(q - 0) = (x + 5)/(p + 5)

x = 2p - 5, y = 2pq/(p + 5)

F(2p - 5, 2pq/(p + 5))

tan∠EOF = EF/OE = 2pq/[(p + 5)|(2p - 5)|] (因为2p - 5可以为负值)

tan∠BDE = EB/DE = (10 - 2p)/(2q) = (5 - p)/q

tan∠DBE = DE/BE = 2q/(10 - 2p) = q/(5 - p)

(i)如∠EOF和∠BDE为对应角2pq/[(p + 5)|(2p - 5)|] = (5 - p)/q

2p/|2p - 5| = (25 - p²)/q² = q²/q² = 1

2p = |2p - 5|

p = 5/4, E(-5/2, 0)

(ii) 如∠EOF和∠DBE为对应角

2pq/[(p + 5)|(2p - 5)|] = q/(5 - p)

(a) p >= 5/2

4p² - 5p - 25 = 0

p = 5(1 + √17)/8

E(5(√17 - 3)/4, 0)

(b) 0 < p < 5/2

p = 5/3

E(-5/3, 0)