(1-1/2²)(1-1/3²)…(1-1/2011²)(1-1/2012²)
2个回答

(1-1/2^2)(1-1/3^2)(1-1/4^2)···(1-1/n^2)···(1-1/100^2)

=(i=2,100)∏(1-1/i^2)

=(i=2,100)∏[(1+1/i)(1-1/i)]

=(i=2,100)∏(1+1/i)×(i=2,100)∏(1-1/i)

=[(3/2)×(4/3)×(5/4)×···×(101/100)]

×[(1/2)×(2/3)×(3/4)×···×(99/100)]

=(101/2)×(1/100)

=101/200

____∏是求积符合,和求和符号∑是一样的!用∏,可以节约很多笔墨,思路清晰,不易出错,用它好啊