(1)Sn=(2^2+2^4+2^6+…+2^2n)-(2+2^2+2^3+…+2^n) (这是两个等比数列)
=(4(1-4^n)/1-4)-(2(1-2^n)/1-2)
=4^(n+1)/3-2^(n+1)+2/3
(2) Tn=2^n/(4^(n+1)/3-2^(n+1)+2/3)=3*2^n/(2^(n+1)-2)(2^(n+1)-1)
=3*2^n*(1/(2^(n+1)-2)-1/(2^(n+1)-1))
=3/(2-1/2^(n-1))-3/(2-1/2^n) (前后项都消掉,只剩下两项)
=3(1-1/(2-1/2^n)