(2)设l1:y=kx+1,{x^2=4y},x^2-4k-4=0,设A(x1,y1),B(x2,y2)x1+x2=4k,x1*x2=-4
AO:y=(y1/x1)x,M点XM=2x1/(x1-y1)
MN^2=2*(xm-xn)^2=2*[(x2y1-x1y2)/(x1-y1)(x2-y2)]^2=2*{(x1-x2)/[(k-1)x1+1][(k-1)x2+1]}^2
MN^2/2=[(4k)^2-4*(-4)]/{[(k-1)^2*(-4)+(k-1)4k+1]^2}=(16k^2+16)/[(4k-3)^2]
=(16k^2-24k+9+24k-18+25)/(16k^2-24k+9)=1+6/(4k-3)+25/(4k-3)^2
设f(x)=25x^2+6x+1,最小值=0.64,Mn最小值=0.8*根号下2