若m^2+n^2-n+4m+17/4=0,m=____,n=_____
1个回答

m²+n²-n+4m+17/4=0

(m+2)²+(n-1/2)²=0

m=-2,n=1/2

(1)=4x²-12xy+9y²-9x²+y²=-5x²-12xy+10y²

(2)=(x²-y²)(x²+y²)=x^4-y^4

(3)=m²+n²+9-2mn-6m+6n