高一数学题,求高手,在线等,急~!
2个回答

①sin3π/8*cosπ/8+cos3π/8*sinπ/8=sin(3π/8+π/8)=sinπ/2=1

②原式=sin(3π/7)*cos(2π/5)+cos(3π/7)*sin(2π/5) (化为同角)

=sin(3π/7+2π/5) (两角和的正弦公式的逆运用)

=sin(29π/35)=sin(6π/35)(互补两角的正弦相等)

原式=sin[α+(π/4)]cosπ/4-cos[(π/4)+α]sinπ/4

=sin[α+(π/4)-(π/4)]=sinα