求弧长和圆的半径题意不全,我帮你补充一下:一未知圆形从边到圆心取半径的700为点画一条垂直与此半径的直线交于圆边的两点A
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一未知圆形从边到圆心取半径的H=700为点画一条垂直与此半径的直线交于圆边的两点A和B,线段AB长L=1800,求圆的半径R是多少?弧长C多少?

圆心角为A.

R^2=(R-H)^2+(L/2)^2

R^2=R^2-2*R*H+H^2+L^2/4

2*R*H=H^2+L^2/4

R=H/2+L^2/(8*H)

=700/2+1800^2/(8*700)

=350+4050/7

=6500/7

=928又(4/7)

=928.571

A=2*ARC SIN((L/2)/R)

=2*ARC SIN((1800/2)/928.571)

=151.5度

=151.5*PI/180

=2.644弧度

C=A*R

=2.644*928.571

=2455.3