将4.34gNa、Na2O、Na2O2的混合物与足量水反应,在标准状况下得到372ml的混合气体,将该混合气体通过放电恰
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2Na+2H2O=2NaOH+H2 ↑

Na2O+H2O=2NaOH

2Na2O2+2H2O=4NaOH+O2↑

所以混合气体为氢气与氧气的混合物.又

2H2+O2=2H2O

体积,氧:氢=1:2

n(H2)=2/3x0.372/22.4=0.011mol

n(O2)=1/3x0.372/22.4=0.0055mol

n(Na)=0.022mol m(Na)=0.022x23=0.506g

n(Na2O2)=0.011mol m(Na2O2)=0.011x78=0.858g

m(Na2O)=4.34-0.858-0.506=2.976g

n(Na2O)=2.97662=0.048mol

n(Na) :n(Na2O) :n(Na2O2)=0.022 :0.048 :0.011=22 :48 :11