1.设袋中有k号的球k只(k=1,2,…,n),从中摸出一球,则所得号码的数学期望为( ) A.(2n+1)/3 B.2
1个回答

共有球1+2+3+...+n=n(n+1)/2只.

1²+2²+...+n²=n(n+1)(2n+1)/6

分布列

X 1 2 ...k ...n

P 1/[n(n+1)/2] 2/[n(n+1)/2] ...k/[n(n+1)/2] ...n/[n(n+1)/2]

EX=2(1²+2²+...+n²)1/[n(n+1)/2]=(2n+1)/3.