初二整式的乘除1.[(-3mn^2*m^2)^3]^22.已知a^n=1/3,b^2n=3,求（a^2*b^3)^4n的
1个回答
1.[(-3mn^2*m^2)^3]^2
=[(-3m^3n^2)^3]^2
=[-27m^9n^6]^2
=729m^18n^12
2.已知a^n=1/3,b^2n=3,求（a^2*b^3)^4n的值
（a^2*b^3)^4n=a^8nb^12n=(a^n)^8(b^2n)^6
=(1/3)^8(3)^6
=[(1/3)*3]^6*[(1/3)^2
=[1]^6*[(1/3)^2
=1*[(1/3)^2
=1/9
3.0.25^99*4^100-8^100*(1/2)^300
=[0.25*4]^99*4-[2^300*(1/2)^300]
=[1]^99*4-[(2*1/2)]^300
=1*4-1^300
=4-1
=3
4.(0.5*11/3)^2008*(-2*3/11)^2007
=(-0.5*2*11/3*3/11)^2007*(0.5*11/3)
=[-1]^2007*(0.5*11/3)
=-1*0.5*11/3
=-11/6
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