2[10x+(x-4)] - 10[(x-4)+x] = 12
1个回答

2[10x+(x-4)] - 10[(x-4)+x] = 12

2[10x+x-4] - 10[x-4+x] = 12

2[11x-4] - 10[2x-4] = 12

[11x-4] - 5[2x-4] = 6

11x-4 - 10x+20= 6

11x - 10x+20-4= 6

x+16=6

x=6-16

x=-10