已知弦长6.5米,拱高0.6米,求弧长?(请给去详细计算公式)急!
1个回答

已知弦长L=6.5米,拱高H=0.6米,求弧长C?

弧半径为R,弧所对的圆心角为A.

R^2=(R-H)^2+(L/2)^2

R^2=R^2-2*R*H+H^2+L^2/4

2*R*H=H^2+L^2/4

R=H/2+L^2/(8*H)

=0.6/2+6.5^2/(8*0.6)

=9.102米

A=2*ARC SIN((L/2)/R)

=2*ARC SIN((6.5/2)/9.102)

=41.84度

=41.84*PI/180

=0.73024弧度

C=A*R

=0.73024*9.102

=6.647米