已知f(x)=sin4次方x+2倍根3sinx*cosx-cos4次方x
2个回答

已知f(x)=sin⁴x+2(√3)sinxcosx-cos⁴x

(1)最小正周期

(2)f(x)的最小值及x的取值范围

(3)单调区间

f(x)=sin⁴x-cos⁴x-2(√3)sinxcosx=(sin²x+cos²x)(sin²x-cos²x)-(√3)sin2x

=sin²x-cos²x-(√3)sin2x=-cos2x-(√3)sin2x=-2[cos2xcos(π/3)+sin2xsin(π/3)]

=-2cos(2x-π/3)

Tmin=2π/2=π

mixf(x)=-2

由2kπ≤2x-π/3≤2kπ+π,π/3+2kπ≤2x≤2kπ+4π/3,

得单增区间:π/6+kπ≤x≤kπ+2π/3 K∈Z

由-π+2kπ≤2x-π/3≤2kπ,-2π/3+2kπ≤2x≤2kπ+π/3

得单减区间:-π/3+kπ≤x≤kπ+π/6 k∈Z