x3+y3+z3-3xyzx8+x6+x4+x2+1
1个回答

1、x^3+y^3+z^3-3xyz

= (x^3+3yx^2+3xy^2+y^3)+z^3-3xyz-3yx^2-3xy^2

= (x+y)^3+z^3-3xy(x+y+z)

= (x+y+z)[(x+y)^2-(x+y)z+z^2]-3xy(x+y+z)

= (x+y+z)[(x^2+2xy+y^2-xz-yz+z^2)-2xy]

= (x+y+z)(x^2+y^2+z^2-xy-yz-zx)

2、等比数列求和公式x^8+x^6+x^4+x^2+1=(1-x^10)/(1-x^2)(x≠1和-1)