1、将一多项式[(17 x²-3x+4)(a x²+bx+c)],除以(5x+6)后,得商式为(2x
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2、已知(19x-31)(13x-17)-(13x-17)(11x-23)可因式分解成(ax+b)(8x+c),其中a、b、c均为整数,则a+b+c=?

(19x-31)(13x-17)-(13x-17)(11x-23)

=(13x-17)(19x-31-11x+23)

=(13x-17)(8x-8)

=(ax+b)(8x+c)

a=13,b=-17,c=8

3、若|m-n|=n-m,且|m|=4,|n|=3则(m+n)²=?

|m-n|=n-m,n>m

|m|=4,m=±4

|n|=3,n=±3

所以,n = ±3,m = -4

(m+n)²=(-4+3)²=1

或者,(m+n)²=(-4-3)²=49

4、若a=2007 / 2008,b=2008 / 2009试不用将分数化小数的方法比较a、b大小.

a = 2007 / 2008 = (2007 X 2009)/(2008 X 2009)=(2008² - 1)/(2008 X 2009)

b = 2008 / 2009 = (2008 X 2008 )/ (2008 X 2009)

所以,a<b

5、已知x²-5x=14,求(x-1)(2x-1)-(x+1)²+1的值

(x-1)(2x-1)-(x+1)²+1

= 2x² - 3x + 1 - x² -2x -1 + 1

= x² - 5x + 1

= 14 + 1

= 15

6、√6 ÷√3 = √2