a²+2ab+b²-ac-bc a²-2ab+b²-m²-2mn-n&
1个回答

a²+2ab+b²-ac-bc

=(a+b)²-c(a+b)

=(a+b)(a+b-c)

a²-2ab+b²-m²-2mn-n²

=(a-b)²-(m+n)²

=(a-b-m-n)(a-b+m+n)

4a²+4a-4a²b+b+1

=(2a+1)²-b(2a-1)(2a+1)

=(2a+1)(2a+1-2ab+b)

ax²+16ay²-a-8axy

=a(x²-8xy+16y²-1)

=a[(x-4y)²-1]

=a(x-4y-1)(x-4y+1)