计算(2+1)(2^2+1)(2^4+1)(2^6+1)(2^8+1)……(2^2n+1)!
1个回答

(2+1)(2^2+1)(2^4+1)(2^6+1)(2^8+1)……(2^2n+1)

=(2-1)[(2+1)(2^2+1)(2^4+1)(2^6+1)(2^8+1)……(2^2n+1)]

=[(2-1)(2+1)](2^2+1)(2^4+1)(2^6+1)(2^8+1)……(2^2n+1)

=(2^2-1)(2^2+1)(2^4+1)(2^6+1)(2^8+1)……(2^2n+1)

=[(2^2-1)(2^2+1)](2^4+1)(2^6+1)(2^8+1)……(2^2n+1)

=(2^4-1)(2^4+1)(2^6+1)(2^8+1)……(2^2n+1)

...

=(2^2n -1)(2^2n+1)

=2^(2n+2)-1