小弟有几个Haskell问题想问大神
1个回答
第一道用了一个比较笨的办法,而且也没有管列表长度小于2的情况
```haskell
splits xs = sp ((length xs)-1) xs
sp 1 xs = [splitAt 1 xs]
sp n xs = (sp (n-1) xs) ++ [splitAt n xs]
```
第二道题copy自[stackoverflow](http://stackoverflow.com/a/21722065/2214113)
```haskell
commonPrefix :: (Eq e) => [e] -> [e] -> [e]
commonPrefix _ [] = []
commonPrefix [] _ = []
commonPrefix (x:xs) (y:ys)
| x == y = x : commonPrefix xs ys
| otherwise = []
cpfx :: (Eq a) => [[a]] -> [a]
cpfx = foldl1 commonPrefix
```
该睡了,后面两个改天有时间再说,我才不告诉你我不会.
