(1)x²/x-1 -x-1这是分式的混合运算,
1个回答

(1)x²/x-1 -x-1

=x²/(x-1)-(x+1)(x-1)/(x-1)

=[x²-(x+1)(x-1)]/(x-1)

=1/(x-1)

(2)x²+2x/x²-4 - 2/x-2

=x(x+2)/(x+2)(x-2)-2/(x-2)

=x/(x-2)-2/(x-2)

=(x-2)/(x-2)

=1

(3)(x/x+1 - 3x/x-1)÷ x/x²-1

=x/(x+1)× (x+1)(x-1)/x -3x/(x-1)× (x+1)(x-1)/x

=x-1-3x-3

=-2x-4

(4)(1+ 2b/a-b)² · (1- 2b/a+b)²

=(a-b+2b)²/(a-b)² ×(a+b-2b)²/(a+b)²

=(a+b)²/(a-b)² ×(a-b)²/(a+b)²

=1