已知函数f(x)=sin(x+π/6)+2sin∧2 x/2,求f(x)最大值
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f(x)=sin(x+π/6)+2sin∧2 x/2

=sin(x+π/6)+1-cosx

=sinxcos(π/6)+cosxsin(π/6)+1-2cosxsin(π/6)

=sinxcos(π/6)-cosxsin(π/6)+1

=sin(x-π/6)+1

-2≤f(x)≤2

f(x)最大值是2

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