a(n)=a+(n-1)c,b(n)=b+(n-1)d,n=1,2,...
S(n)=na+n(n-1)c/2,T(n)=nb+n(n-1)d/2.
(1+1)/1=S(1)/T(1)=a/b,a=2b.
(2+1)/2=S(2)/T(2)=[2a+c]/[2b+d],3(2b+d)=2(2a+c),
2c=3d-2b.
(3+1)/3=S(3)/T(3)=[3a+3c]/[3b+3d],4(b+d)=3(a+c),
8(b+d)=3(2a+2c)=3(4b+3d-2b)=3(2b+3d),
d=2b.
2c=3d-2b=4b,c=2b.
a(10)/b(10)=[a+9c]/[b+9d]=[2b+18b]/[b+18b]=20/19