计算(3y)分之2x+(3y)分之5x
1个回答

(3y)分之2x+(3y)分之5x

=(3y)分之(2x+5x)

=(3y)分之(7x)

(x+y)分之2y-(y+x)分之y-x

=(x+y)分之2y-(x+y)分之(y-x)

=(x+y)分之(2y-y+x)

=(x+y)分之(x+y)

=1

(x²+3x)分之x²+9x+(x²+6x+9)分之x²-9

=x(x+3)分之x(x+9)+(x+3)²分之(x²-9)

=(x+3)²分之(x+3)(x+9)+(x+3)²分之(x²-9)

=(x+3)²分之[(x+3)(x+9)+(x²-9)]

=(x+3)²分之(x²+12x+27+x²-9)

=(x+3)²分之(2x²+12x+18)

=(x+3)²分之2(x+3)²

=2