甲乙两个扇形的半径之比为4:5,面积的比是2:3,如果扇形甲的圆心角为80度,那么扇形乙的圆心角为多少度?
1个回答

扇形甲的面积=r²π/n.

扇形乙的面积=R²π/m.

那么半径之比为 r:R=4:5,

面积的比是 (r²π/n):(R²π/m)=2:3,

(r²π/n)/(R²π/m)=(m/n)(r/R)²=(m/n)(4/5)²=(16m)/(25n)

∵(r²π/n):(R²π/m)=2:3

∴(16m)/(25n)=2/3

m/n=25/24,m=25n/24.

如果扇形甲的圆心角为80度 360°/80°=n,n=9/2.

m=25/24*9/2=225/48.

扇形乙的圆心角为 360°/m=360°/(225/48)=360°*(48/225)=76.8°