1.公差d
s3=3a2=12
a2=4
(a2)^2=(2a2-2d)*(a2+d+1)
16=(8-2d)(d+5)
(d-3)(d+4)=0
d=3
an=3n-2
2.bn=an/3^n=(3n-2)/(3^n)
Tn=1/3+4/3^2+……+(3n-5)/(3^(n-1))+(3n-2)/(3^n)
3Tn=1+4/3+7/3^2+……+(3n-2)/(3^(n-1))
想减2Tn=1+1+1+……+1-(3n-2)/(3^n)=n-(3n-2)/(3^n)
Tn=n/2-(3n-2)/(3^n)