(2x一1)^2(3x+2)一(2x一1)(3x+2)^2一x(1一2x)(3x+2)^2,其中x等于2分之3.要先分解
1个回答

原式=(2x-1)^2(3x+2)-(2x-1)(3x+2)^2+x(2x-1)(3x+2)^2

=(2x-1)(3x+2)(2x-1-(3x+2)+x(3x+2))

=(6x^2+4x-3x-2)(2x-1-3x-2+x^2+2x)

=(6x^2+x-2)(x^2+x-3)

当x=3/2时

原式=(6*(9/4)+(3/2)-2)((9/4)+(3/2)-3)

=((54/4)+(6/4)-(8/4))((9/4)+(6/4)-(12/4))

=(52/4)(3/4)

=156/16

=9.75