(16x-13)/(4x-3)+(40x-43)/(8x-9)=(32x-30)/(8x-7)+(20x-24)/(4x
1个回答

(16x-13)/(4x-3)+(40x-43)/(8x-9)=(32x-30)/(8x-7)+(20x-24)/(4x-5)

4-1/(4x-3)+5+2/(8x-9)=4-2/(8x-7)+5+1/(4x-5)

2/(8x-9)+2/(8x-7)=1/(4x-3)+1/(4x-5)

2(8x-9+8x-7)/[(8x-9)(8x-7)]=(4x-3+4x-5)/[(4x-3)(4x-5)]

2(16x-16)/[(8x-9)(8x-7)]=(8x-8)/[(4x-3)(4x-5)] 其中x=1时等式恒成立 若x≠1时可化为

4(4x-3)(4x-5)=(8x-9)(8x-7)

64x²-128x+60=64x²-128x+63

等式不成立

所以方程的解为x=1