(1)923−9923+99923=
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解题思路:(1)整数部分相加减,分数部分相加减;

(2)根据乘法分配律约分计算;

(3)提公因数4.9计算;

(4)提公因数,即原式=9999×(1+9999);

(5)原式=12×13×(11-1)-260;

(6)原式=999×(101×99+1)=999×[(100+1)×99+1];

(7)提公因数5.25计算即可;

(8)原式=199.9×(1880-1879).

(1)9

2

3−99

2

3+999

2

3,

=(9+999-99)+([2/3]+[2/3]-[2/3])

=909+[2/3],

=909[2/3];

(2)(

3

8+

1

6−

2

9)×72,

=[3/8]×72+[1/6]×72-[2/9]×72,

=27+12-16,

=23;

(3)4.9×5

1

2+4.9+3

1

2×4.9,

=4.9×(5.5+1+3.5),

=4.9×10,

=49;

(4)9999+99992

=9999×(1+9999),

=9999×10000,

=99990000;

(5)11×12×13-12×13-260,

=(11-1)×12×13-260,

=10×12×13-260,

=1560-260,

=1300;

(6)101×99×999+999,

=999×(101×99+1),

=999×[(100+1)×99+1];

=999×[100×99+99+1],

=999×[9900+99+1],

=999×10000,

=9990000;

(7)5

1

4×3.8+6.2×5.25,

=5.25×(3.8+6.2),

=5.25×10,

=52.5;

(8)1880×199.9-1999×187.9,

=1880×199.9-199.9×1879,

=(1880-1879)×199.9,

=1×199.9,

=199.9.

点评:

本题考点: 分数的四则混合运算;整数四则混合运算;运算定律与简便运算.

考点点评: 考查了运算定律与简便运算,四则混合运算.注意运算顺序和运算法则,灵活运用所学的运算律简便计算.

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