(1)√12-√1/3=?(2)√8/2+2√18-1/4√32=?(3)√20×√5-8=?(4)(√8/27-5√6
1个回答

(1)√12-√1/3

=2√3-√3/3

=5√3/3;

(2)√8/2+2√18-1/4√32

=2√2/2+2×3√2-4√2/4

=√2+6√2-√2

=6√2;

(3)√20×√5-8

=2√5×√5-8

=2×5-8

=10-8

=2;

(4)(√8/27-5√6)×√6

=2√6/9×√6-5√6×√6

=12/9-30

=4/3-30

=-28-2/3

=-28又3分之2;

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