已知函数f(x)+sin(wx+pi/6)+根号3cos(wx+pi/6)(w>0)
1个回答

f(x)=sin(wx+pi/6)+根号3cos(wx+pi/6)

=2sin(wx+π/2)

=2coswx

1. 函数y=f(x)图象的两相邻对称轴间的距离为Pi/2

则周期T=2π/w=2*π/2

解得w=2

所以f(x)=2cos2x

2. 依题意y=g(x)=2cos(8x+π/6)

单减区间8x+π/6∈[2kπ+π/2, 2kπ+3π/2]

x∈[kπ/4+π/24, kπ/4+π/6]

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