一个不定积分问题∫x^2*arctan(7x)dx...
1个回答

要用分部积分法

∫x^2*arctan(7x)dx

=(x^3/3)*arctan(7x)-∫(x^3/3)*7/(49x^2+1)

=(x^3/3)*arctan(7x)-7/6∫x^2/(49x^2+1)d(x^2)

=(x^3/3)*arctan(7x)-(x^2/42-(1/2048)*ln|x^2+1/49|)

=(x^3/3)*arctan(7x)-x^2/42+(1/2048)*ln|x^2+1/49|+C