甲乙丙所需天数分别是x,y,z,根据已知有
x = a(y+z),a = x / (y+z),a+1 = (x+y+z) / (y+z)
y = b(x+z),b = y / (x+z),b+1 = (x+y+z) / (x+z)
z = c(x+y),c = z / (x+y),c+1 = (x+y+z) / (x+y)
所以
1/(a+1) + 1/(b+1) + 1/(c+1)
= (y+z) / (x+y+z) + (x+z) / (x+y+z) + (x+y) / (x+y+z)
= (y+z + x+z + x+y) / (x+y+z)
= 2