【答】:盐酸的质量的质量为: 94.8 g
设:NaOH xmol, Na2CO3 ymol.
NaOH + HCl = NaCl + H2O
..x.x
Na2CO3 + 2HCl = 2NaCl + CO2 + H2O
..y.2y.y
y = 2.2/44 = 0.05 mol
40x + 106y = 9.3
x = 0.1 mol
参加反应的n(HCl) = x + 2y = 0.1 + 0.05*2 = 0.2 mol
m(HCl) = 0.2 * 36.5 / 7.7% = 94.8(g)