解方程的结果!sqrt((x-x1)^2+(y-y1)^2+(z-z1)^2)=R sqrt((x-x2)^2+(y-y
3个回答

(x-x1)^2+(y-y1)^2+(z-z1)^2=R^2……1

(x-x2)^2+(y-y2)^2+(z-z2)^2=R^2……2

(x-x3)^2+(y-y3)^2+(z-z3)^2=R^2……3

(1-2）:x(x2-x1)+(x1^2-x2^2)+y(y2-y1)+(y1^2-y2^2)+z(z2-z1)+(z1^2-z2^2)=0

(1-3) :x(x3-x1)+(x1^2-x3^2)+y(y3-y1)+(y1^2-y3^2)+z(z3-z1)+(z1^2-z3^2)=0

(2-3) :x(x3-x2)+(x2^2-x3^2)+y(y3-y2)+(y2^2-y3^2)+z(z3-z2)+(z2^2-z3^2)=0

再用它们解一次方程组就是了

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